I was playing at Roy Hoppe's club with Dave Neuman today. Dave made an imaginative bid that worked well. He dealt and held, with neither side vulnerable:
♠ AKQTxx
♥ AJ
♦ Kx
♣ Jxx
He bid 1 Spade. LHO overcalled 2 Clubs. I passed. RHO advanced 2 Diamonds. Back to him. What would you do?
Dave eschewed such mundane bids as 2 or 3 Spades. Instead, he chose to bid 3 Diamonds! Dave and I have an agreement that when the opponents have bid two suits, a cue bid of one of them shows a stopper in that suit but not the other. So he showed a diamond stopper and asked me to bid 3NT with a club stopper. While it is true that this would only produce the eighth trick if spades ran, he decided to go for it since I might have something else useful that would produce another. I held
♠ xxx
♥ T98
♦ QJx
♣ Q9xx
Not much, but when they didn't find the potentially killing heart lead, it was enough. RHO played the ten to my queen, so the 9 was a second stopper. If he instead won it with the king, there was no defense (hearts cannot be led from his side without setting up 2 tricks in the suit). I only needed to play a diamond and that was 9 tricks (spades were 3-1). I actually made ten, since when I led a diamond, LHO went up with the ace and I unblocked the king. (If he ducked, there would only be 9 since I wouln't be able to set up another diamond and untangle all the tricks.) +430 was a cold top. +400 would have still been a top; everybody else was in 3 or 4 Spades.
Good luck!
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